3(3y-2)=-32

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Solution for 3(3y-2)=-32 equation: 



3(3y-2)=-32

We move all terms to the left:

3(3y-2)-(-32)=0

We add all the numbers together, and all the variables

3(3y-2)+32=0

We multiply parentheses

9y-6+32=0

We add all the numbers together, and all the variables

9y+26=0

We move all terms containing y to the left, all other terms to the right

9y=-26

y=-26/9

y=-2+8/9

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