3(3y-3)-10=3(y+5)+2

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Solution for 3(3y-3)-10=3(y+5)+2 equation: 



3(3y-3)-10=3(y+5)+2

We move all terms to the left:

3(3y-3)-10-(3(y+5)+2)=0

We multiply parentheses

9y-(3(y+5)+2)-9-10=0



We calculate terms in parentheses: -(3(y+5)+2), so:

3(y+5)+2

We multiply parentheses

3y+15+2

We add all the numbers together, and all the variables

3y+17

Back to the equation:

-(3y+17)



We add all the numbers together, and all the variables

9y-(3y+17)-19=0

We get rid of parentheses

9y-3y-17-19=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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