3(3y-3)-2(y+2)=4-3(y+2)

Solution for 3(3y-3)-2(y+2)=4-3(y+2) equation:

3(3y-3)-2(y+2)=4-3(y+2)

We move all terms to the left:

3(3y-3)-2(y+2)-(4-3(y+2))=0

We multiply parentheses

9y-2y-(4-3(y+2))-9-4=0


We calculate terms in parentheses: -(4-3(y+2)), so:

4-3(y+2)

determiningTheFunctionDomain
-3(y+2)+4

We multiply parentheses

-3y-6+4

We add all the numbers together, and all the variables

-3y-2

Back to the equation:

-(-3y-2)


We add all the numbers together, and all the variables

7y-(-3y-2)-13=0

We get rid of parentheses

7y+3y+2-13=0

We add all the numbers together, and all the variables

10y-11=0

We move all terms containing y to the left, all other terms to the right

10y=11

y=11/10

y=1+1/10