3(3y-3)-y=8

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Solution for 3(3y-3)-y=8 equation:



3(3y-3)-y=8
We move all terms to the left:
3(3y-3)-y-(8)=0
We add all the numbers together, and all the variables
-1y+3(3y-3)-8=0
We multiply parentheses
-1y+9y-9-8=0
We add all the numbers together, and all the variables
8y-17=0
We move all terms containing y to the left, all other terms to the right
8y=17
y=17/8
y=2+1/8

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