3(3y-3)=27

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Solution for 3(3y-3)=27 equation: 



3(3y-3)=27

We move all terms to the left:

3(3y-3)-(27)=0

We multiply parentheses

9y-9-27=0

We add all the numbers together, and all the variables

9y-36=0

We move all terms containing y to the left, all other terms to the right

9y=36

y=36/9

y=4

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