3(3y-34)=y+16

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Solution for 3(3y-34)=y+16 equation: 



3(3y-34)=y+16

We move all terms to the left:

3(3y-34)-(y+16)=0

We multiply parentheses

9y-(y+16)-102=0

We get rid of parentheses

9y-y-16-102=0

We add all the numbers together, and all the variables

8y-118=0

We move all terms containing y to the left, all other terms to the right

8y=118

y=118/8

y=14+3/4

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