3(3y-4)+3=3(y+2)+9

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Solution for 3(3y-4)+3=3(y+2)+9 equation:



3(3y-4)+3=3(y+2)+9
We move all terms to the left:
3(3y-4)+3-(3(y+2)+9)=0
We multiply parentheses
9y-(3(y+2)+9)-12+3=0
We calculate terms in parentheses: -(3(y+2)+9), so:
3(y+2)+9
We multiply parentheses
3y+6+9
We add all the numbers together, and all the variables
3y+15
Back to the equation:
-(3y+15)
We add all the numbers together, and all the variables
9y-(3y+15)-9=0
We get rid of parentheses
9y-3y-15-9=0
We add all the numbers together, and all the variables
6y-24=0
We move all terms containing y to the left, all other terms to the right
6y=24
y=24/6
y=4

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