3(3y-4)=3(4y-5)

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Solution for 3(3y-4)=3(4y-5) equation: 



3(3y-4)=3(4y-5)

We move all terms to the left:

3(3y-4)-(3(4y-5))=0

We multiply parentheses

9y-(3(4y-5))-12=0



We calculate terms in parentheses: -(3(4y-5)), so:

3(4y-5)

We multiply parentheses

12y-15

Back to the equation:

-(12y-15)



We get rid of parentheses

9y-12y+15-12=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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