3(3y-5)=42

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Solution for 3(3y-5)=42 equation: 



3(3y-5)=42

We move all terms to the left:

3(3y-5)-(42)=0

We multiply parentheses

9y-15-42=0

We add all the numbers together, and all the variables

9y-57=0

We move all terms containing y to the left, all other terms to the right

9y=57

y=57/9

y=6+1/3

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