3(3y-6)=7y-18+2y

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Solution for 3(3y-6)=7y-18+2y equation:


Simplifying
3(3y + -6) = 7y + -18 + 2y

Reorder the terms:
3(-6 + 3y) = 7y + -18 + 2y
(-6 * 3 + 3y * 3) = 7y + -18 + 2y
(-18 + 9y) = 7y + -18 + 2y

Reorder the terms:
-18 + 9y = -18 + 7y + 2y

Combine like terms: 7y + 2y = 9y
-18 + 9y = -18 + 9y

Add '18' to each side of the equation.
-18 + 18 + 9y = -18 + 18 + 9y

Combine like terms: -18 + 18 = 0
0 + 9y = -18 + 18 + 9y
9y = -18 + 18 + 9y

Combine like terms: -18 + 18 = 0
9y = 0 + 9y
9y = 9y

Add '-9y' to each side of the equation.
9y + -9y = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 9y + -9y

Combine like terms: 9y + -9y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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