3(3y-7)=2y+7

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Solution for 3(3y-7)=2y+7 equation: 



3(3y-7)=2y+7

We move all terms to the left:

3(3y-7)-(2y+7)=0

We multiply parentheses

9y-(2y+7)-21=0

We get rid of parentheses

9y-2y-7-21=0

We add all the numbers together, and all the variables

7y-28=0

We move all terms containing y to the left, all other terms to the right

7y=28

y=28/7

y=4

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