3(3y-8)=2(y-4)+3y

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Solution for 3(3y-8)=2(y-4)+3y equation:



3(3y-8)=2(y-4)+3y
We move all terms to the left:
3(3y-8)-(2(y-4)+3y)=0
We multiply parentheses
9y-(2(y-4)+3y)-24=0
We calculate terms in parentheses: -(2(y-4)+3y), so:
2(y-4)+3y
We add all the numbers together, and all the variables
3y+2(y-4)
We multiply parentheses
3y+2y-8
We add all the numbers together, and all the variables
5y-8
Back to the equation:
-(5y-8)
We get rid of parentheses
9y-5y+8-24=0
We add all the numbers together, and all the variables
4y-16=0
We move all terms containing y to the left, all other terms to the right
4y=16
y=16/4
y=4

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