3(3z+1)=4(2z-2)

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Solution for 3(3z+1)=4(2z-2) equation:



3(3z+1)=4(2z-2)
We move all terms to the left:
3(3z+1)-(4(2z-2))=0
We multiply parentheses
9z-(4(2z-2))+3=0
We calculate terms in parentheses: -(4(2z-2)), so:
4(2z-2)
We multiply parentheses
8z-8
Back to the equation:
-(8z-8)
We get rid of parentheses
9z-8z+8+3=0
We add all the numbers together, and all the variables
z+11=0
We move all terms containing z to the left, all other terms to the right
z=-11

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