3(3z+2)=2-2(z-2)

Solution for 3(3z+2)=2-2(z-2) equation:

Simplifying
3(3z + 2) = 2 + -2(z + -2)

Reorder the terms:
3(2 + 3z) = 2 + -2(z + -2)
(2 * 3 + 3z * 3) = 2 + -2(z + -2)
(6 + 9z) = 2 + -2(z + -2)

Reorder the terms:
6 + 9z = 2 + -2(-2 + z)
6 + 9z = 2 + (-2 * -2 + z * -2)
6 + 9z = 2 + (4 + -2z)

Combine like terms: 2 + 4 = 6
6 + 9z = 6 + -2z

Add '-6' to each side of the equation.
6 + -6 + 9z = 6 + -6 + -2z

Combine like terms: 6 + -6 = 0
0 + 9z = 6 + -6 + -2z
9z = 6 + -6 + -2z

Combine like terms: 6 + -6 = 0
9z = 0 + -2z
9z = -2z

Solving
9z = -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
9z + 2z = -2z + 2z

Combine like terms: 9z + 2z = 11z
11z = -2z + 2z

Combine like terms: -2z + 2z = 0
11z = 0

Divide each side by '11'.
z = 0

Simplifying
z = 0