3(3z+3)-5z-4=25

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Solution for 3(3z+3)-5z-4=25 equation: 



3(3z+3)-5z-4=25

We move all terms to the left:

3(3z+3)-5z-4-(25)=0

We add all the numbers together, and all the variables

-5z+3(3z+3)-29=0

We multiply parentheses

-5z+9z+9-29=0

We add all the numbers together, and all the variables

4z-20=0

We move all terms containing z to the left, all other terms to the right

4z=20

z=20/4

z=5

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