3(3z+4)=12-z

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Solution for 3(3z+4)=12-z equation: 



3(3z+4)=12-z

We move all terms to the left:

3(3z+4)-(12-z)=0

We add all the numbers together, and all the variables

3(3z+4)-(-1z+12)=0

We multiply parentheses

9z-(-1z+12)+12=0

We get rid of parentheses

9z+1z-12+12=0

We add all the numbers together, and all the variables

10z=0

z=0/10

z=0

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