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3(3z+5)=2(5z+3)
We move all terms to the left:
3(3z+5)-(2(5z+3))=0
We multiply parentheses
9z-(2(5z+3))+15=0
We calculate terms in parentheses: -(2(5z+3)), so:We get rid of parentheses
2(5z+3)
We multiply parentheses
10z+6
Back to the equation:
-(10z+6)
9z-10z-6+15=0
We add all the numbers together, and all the variables
-1z+9=0
We move all terms containing z to the left, all other terms to the right
-z=-9
z=-9/-1
z=+9
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