3(3z-28)+2z=54

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Solution for 3(3z-28)+2z=54 equation: 



3(3z-28)+2z=54

We move all terms to the left:

3(3z-28)+2z-(54)=0

We add all the numbers together, and all the variables

2z+3(3z-28)-54=0

We multiply parentheses

2z+9z-84-54=0

We add all the numbers together, and all the variables

11z-138=0

We move all terms containing z to the left, all other terms to the right

11z=138

z=138/11

z=12+6/11

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