3(3z-3)-3(4-4z)=6

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Solution for 3(3z-3)-3(4-4z)=6 equation: 



3(3z-3)-3(4-4z)=6

We move all terms to the left:

3(3z-3)-3(4-4z)-(6)=0

We add all the numbers together, and all the variables

3(3z-3)-3(-4z+4)-6=0

We multiply parentheses

9z+12z-9-12-6=0

We add all the numbers together, and all the variables

21z-27=0

We move all terms containing z to the left, all other terms to the right

21z=27

z=27/21

z=1+2/7

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