3(3z-5)=2z+13

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Solution for 3(3z-5)=2z+13 equation: 



3(3z-5)=2z+13

We move all terms to the left:

3(3z-5)-(2z+13)=0

We multiply parentheses

9z-(2z+13)-15=0

We get rid of parentheses

9z-2z-13-15=0

We add all the numbers together, and all the variables

7z-28=0

We move all terms containing z to the left, all other terms to the right

7z=28

z=28/7

z=4

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