3(3z-7)=2(2z+1)+z

Solution for 3(3z-7)=2(2z+1)+z equation:

3(3z-7)=2(2z+1)+z

We move all terms to the left:

3(3z-7)-(2(2z+1)+z)=0

We multiply parentheses

9z-(2(2z+1)+z)-21=0


We calculate terms in parentheses: -(2(2z+1)+z), so:

2(2z+1)+z

We add all the numbers together, and all the variables

z+2(2z+1)

We multiply parentheses

z+4z+2

We add all the numbers together, and all the variables

5z+2

Back to the equation:

-(5z+2)


We get rid of parentheses

9z-5z-2-21=0

We add all the numbers together, and all the variables

4z-23=0

We move all terms containing z to the left, all other terms to the right

4z=23

z=23/4

z=5+3/4