3(3z-8)+4(-4z+2)=19

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Solution for 3(3z-8)+4(-4z+2)=19 equation:



3(3z-8)+4(-4z+2)=19
We move all terms to the left:
3(3z-8)+4(-4z+2)-(19)=0
We multiply parentheses
9z-16z-24+8-19=0
We add all the numbers together, and all the variables
-7z-35=0
We move all terms containing z to the left, all other terms to the right
-7z=35
z=35/-7
z=-5

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