3(4+(4+3/2z)-2z)=19

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Solution for 3(4+(4+3/2z)-2z)=19 equation: 



3(4+(4+3/2z)-2z)=19

We move all terms to the left:

3(4+(4+3/2z)-2z)-(19)=0



Domain of the equation: 2z)-2z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

3(4+(3/2z+4)-2z)-19=0

We multiply all the terms by the denominator


3(4+(3-19*2z+4)-2z)=0

We add all the numbers together, and all the variables

3(4+(-19*2z+7)-2z)=0

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