3(4+1)+1+2*4=2(2*4+2)+4

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Solution for 3(4+1)+1+2*4=2(2*4+2)+4 equation: 


Simplifying
3(4 + 1) + 1 + 2 * 4 = 2(2 * 4 + 2) + 4

Combine like terms: 4 + 1 = 5
3(5) + 1 + 2 * 4 = 2(2 * 4 + 2) + 4

Multiply 3 * 5
15 + 1 + 2 * 4 = 2(2 * 4 + 2) + 4

Multiply 2 * 4
15 + 1 + 8 = 2(2 * 4 + 2) + 4

Combine like terms: 15 + 1 = 16
16 + 8 = 2(2 * 4 + 2) + 4

Combine like terms: 16 + 8 = 24
24 = 2(2 * 4 + 2) + 4

Multiply 2 * 4
24 = 2(8 + 2) + 4

Combine like terms: 8 + 2 = 10
24 = 2(10) + 4

Multiply 2 * 10
24 = 20 + 4

Combine like terms: 20 + 4 = 24
24 = 24

Add '-24' to each side of the equation.
24 + -24 = 24 + -24

Combine like terms: 24 + -24 = 0
0 = 24 + -24

Combine like terms: 24 + -24 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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