3(4+1)-17=2(3c+2)-3c

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Solution for 3(4+1)-17=2(3c+2)-3c equation: 



3(4+1)-17=2(3c+2)-3c

We move all terms to the left:

3(4+1)-17-(2(3c+2)-3c)=0

We add all the numbers together, and all the variables

-(2(3c+2)-3c)-17+35=0

We add all the numbers together, and all the variables

-(2(3c+2)-3c)+18=0



We calculate terms in parentheses: -(2(3c+2)-3c), so:

2(3c+2)-3c

We add all the numbers together, and all the variables

-3c+2(3c+2)

We multiply parentheses

-3c+6c+4

We add all the numbers together, and all the variables

3c+4

Back to the equation:

-(3c+4)



We get rid of parentheses

-3c-4+18=0

We add all the numbers together, and all the variables

-3c+14=0

We move all terms containing c to the left, all other terms to the right

-3c=-14

c=-14/-3

c=4+2/3

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