3(4+2)-b=27

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Solution for 3(4+2)-b=27 equation: 



3(4+2)-b=27

We move all terms to the left:

3(4+2)-b-(27)=0

determiningTheFunctionDomain
-b-27+3(4+2)=0

We add all the numbers together, and all the variables

-b-27+36=0

We add all the numbers together, and all the variables

-1b+9=0

We move all terms containing b to the left, all other terms to the right

-b=-9

b=-9/-1

b=+9

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