3(4+3n)=4(n-2(

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Solution for 3(4+3n)=4(n-2( equation: 



3(4+3n)=4(n-2(

We move all terms to the left:

3(4+3n)-(4(n-2()=0

We add all the numbers together, and all the variables

3(3n+4)-(4(n-2()=0

We multiply parentheses

9n-(4(n-2()+12=0

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