3(4+3x)+6=32

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Solution for 3(4+3x)+6=32 equation: 



3(4+3x)+6=32

We move all terms to the left:

3(4+3x)+6-(32)=0

We add all the numbers together, and all the variables

3(3x+4)+6-32=0

We add all the numbers together, and all the variables

3(3x+4)-26=0

We multiply parentheses

9x+12-26=0

We add all the numbers together, and all the variables

9x-14=0

We move all terms containing x to the left, all other terms to the right

9x=14

x=14/9

x=1+5/9

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