3(4+6c)+4(2+4c)=

Solution for 3(4+6c)+4(2+4c)= equation:

Simplifying
3(4 + 6c) + 4(2 + 4c) = 0
(4 * 3 + 6c * 3) + 4(2 + 4c) = 0
(12 + 18c) + 4(2 + 4c) = 0
12 + 18c + (2 * 4 + 4c * 4) = 0
12 + 18c + (8 + 16c) = 0

Reorder the terms:
12 + 8 + 18c + 16c = 0

Combine like terms: 12 + 8 = 20
20 + 18c + 16c = 0

Combine like terms: 18c + 16c = 34c
20 + 34c = 0

Solving
20 + 34c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 34c = 0 + -20

Combine like terms: 20 + -20 = 0
0 + 34c = 0 + -20
34c = 0 + -20

Combine like terms: 0 + -20 = -20
34c = -20

Divide each side by '34'.
c = -0.5882352941

Simplifying
c = -0.5882352941