3(4+b)=2b+40

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Solution for 3(4+b)=2b+40 equation: 



3(4+b)=2b+40

We move all terms to the left:

3(4+b)-(2b+40)=0

We add all the numbers together, and all the variables

3(b+4)-(2b+40)=0

We multiply parentheses

3b-(2b+40)+12=0

We get rid of parentheses

3b-2b-40+12=0

We add all the numbers together, and all the variables

b-28=0

We move all terms containing b to the left, all other terms to the right

b=28

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