3(4+b)=8(b-1)

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Solution for 3(4+b)=8(b-1) equation: 



3(4+b)=8(b-1)

We move all terms to the left:

3(4+b)-(8(b-1))=0

We add all the numbers together, and all the variables

3(b+4)-(8(b-1))=0

We multiply parentheses

3b-(8(b-1))+12=0



We calculate terms in parentheses: -(8(b-1)), so:

8(b-1)

We multiply parentheses

8b-8

Back to the equation:

-(8b-8)



We get rid of parentheses

3b-8b+8+12=0

We add all the numbers together, and all the variables

-5b+20=0

We move all terms containing b to the left, all other terms to the right

-5b=-20

b=-20/-5

b=+4

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