3(4+c)=16

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Solution for 3(4+c)=16 equation: 



3(4+c)=16

We move all terms to the left:

3(4+c)-(16)=0

We add all the numbers together, and all the variables

3(c+4)-16=0

We multiply parentheses

3c+12-16=0

We add all the numbers together, and all the variables

3c-4=0

We move all terms containing c to the left, all other terms to the right

3c=4

c=4/3

c=1+1/3

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