3(4+c)=2(c-5)

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Solution for 3(4+c)=2(c-5) equation: 


Simplifying
3(4 + c) = 2(c + -5)
(4 * 3 + c * 3) = 2(c + -5)
(12 + 3c) = 2(c + -5)

Reorder the terms:
12 + 3c = 2(-5 + c)
12 + 3c = (-5 * 2 + c * 2)
12 + 3c = (-10 + 2c)

Solving
12 + 3c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
12 + 3c + -2c = -10 + 2c + -2c

Combine like terms: 3c + -2c = 1c
12 + 1c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
12 + 1c = -10 + 0
12 + 1c = -10

Add '-12' to each side of the equation.
12 + -12 + 1c = -10 + -12

Combine like terms: 12 + -12 = 0
0 + 1c = -10 + -12
1c = -10 + -12

Combine like terms: -10 + -12 = -22
1c = -22

Divide each side by '1'.
c = -22

Simplifying
c = -22

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