3(4+n)=28

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Solution for 3(4+n)=28 equation: 



3(4+n)=28

We move all terms to the left:

3(4+n)-(28)=0

We add all the numbers together, and all the variables

3(n+4)-28=0

We multiply parentheses

3n+12-28=0

We add all the numbers together, and all the variables

3n-16=0

We move all terms containing n to the left, all other terms to the right

3n=16

n=16/3

n=5+1/3

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