3(4+n)=n+6

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Solution for 3(4+n)=n+6 equation: 



3(4+n)=n+6

We move all terms to the left:

3(4+n)-(n+6)=0

We add all the numbers together, and all the variables

3(n+4)-(n+6)=0

We multiply parentheses

3n-(n+6)+12=0

We get rid of parentheses

3n-n-6+12=0

We add all the numbers together, and all the variables

2n+6=0

We move all terms containing n to the left, all other terms to the right

2n=-6

n=-6/2

n=-3

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