3(4+x)=7x-2(x+3)

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Solution for 3(4+x)=7x-2(x+3) equation: 



3(4+x)=7x-2(x+3)

We move all terms to the left:

3(4+x)-(7x-2(x+3))=0

We add all the numbers together, and all the variables

3(x+4)-(7x-2(x+3))=0

We multiply parentheses

3x-(7x-2(x+3))+12=0



We calculate terms in parentheses: -(7x-2(x+3)), so:

7x-2(x+3)

We multiply parentheses

7x-2x-6

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We get rid of parentheses

3x-5x+6+12=0

We add all the numbers together, and all the variables

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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