3(4+y)=2(y+5)

Solution for 3(4+y)=2(y+5) equation:

3(4+y)=2(y+5)

We move all terms to the left:

3(4+y)-(2(y+5))=0

We add all the numbers together, and all the variables

3(y+4)-(2(y+5))=0

We multiply parentheses

3y-(2(y+5))+12=0


We calculate terms in parentheses: -(2(y+5)), so:

2(y+5)

We multiply parentheses

2y+10

Back to the equation:

-(2y+10)


We get rid of parentheses

3y-2y-10+12=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2