3(4-2f)=-2(f+5)

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Solution for 3(4-2f)=-2(f+5) equation: 



3(4-2f)=-2(f+5)

We move all terms to the left:

3(4-2f)-(-2(f+5))=0

We add all the numbers together, and all the variables

3(-2f+4)-(-2(f+5))=0

We multiply parentheses

-6f-(-2(f+5))+12=0



We calculate terms in parentheses: -(-2(f+5)), so:

-2(f+5)

We multiply parentheses

-2f-10

Back to the equation:

-(-2f-10)



We get rid of parentheses

-6f+2f+10+12=0

We add all the numbers together, and all the variables

-4f+22=0

We move all terms containing f to the left, all other terms to the right

-4f=-22

f=-22/-4

f=5+1/2

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