3(4-2f)=4f-28

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Solution for 3(4-2f)=4f-28 equation: 



3(4-2f)=4f-28

We move all terms to the left:

3(4-2f)-(4f-28)=0

We add all the numbers together, and all the variables

3(-2f+4)-(4f-28)=0

We multiply parentheses

-6f-(4f-28)+12=0

We get rid of parentheses

-6f-4f+28+12=0

We add all the numbers together, and all the variables

-10f+40=0

We move all terms containing f to the left, all other terms to the right

-10f=-40

f=-40/-10

f=+4

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