3(4-2j)-j=-11+2(j-11)

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Solution for 3(4-2j)-j=-11+2(j-11) equation:



3(4-2j)-j=-11+2(j-11)
We move all terms to the left:
3(4-2j)-j-(-11+2(j-11))=0
We add all the numbers together, and all the variables
3(-2j+4)-j-(-11+2(j-11))=0
We add all the numbers together, and all the variables
-1j+3(-2j+4)-(-11+2(j-11))=0
We multiply parentheses
-1j-6j-(-11+2(j-11))+12=0
We calculate terms in parentheses: -(-11+2(j-11)), so:
-11+2(j-11)
determiningTheFunctionDomain 2(j-11)-11
We multiply parentheses
2j-22-11
We add all the numbers together, and all the variables
2j-33
Back to the equation:
-(2j-33)
We add all the numbers together, and all the variables
-7j-(2j-33)+12=0
We get rid of parentheses
-7j-2j+33+12=0
We add all the numbers together, and all the variables
-9j+45=0
We move all terms containing j to the left, all other terms to the right
-9j=-45
j=-45/-9
j=+5

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