3(4-2x)+3(4x+8)=72

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Solution for 3(4-2x)+3(4x+8)=72 equation: 



3(4-2x)+3(4x+8)=72

We move all terms to the left:

3(4-2x)+3(4x+8)-(72)=0

We add all the numbers together, and all the variables

3(-2x+4)+3(4x+8)-72=0

We multiply parentheses

-6x+12x+12+24-72=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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