3(4-2x)+4+2x=4x-8(2-x)

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Solution for 3(4-2x)+4+2x=4x-8(2-x) equation:



3(4-2x)+4+2x=4x-8(2-x)
We move all terms to the left:
3(4-2x)+4+2x-(4x-8(2-x))=0
We add all the numbers together, and all the variables
3(-2x+4)+2x-(4x-8(-1x+2))+4=0
We add all the numbers together, and all the variables
2x+3(-2x+4)-(4x-8(-1x+2))+4=0
We multiply parentheses
2x-6x-(4x-8(-1x+2))+12+4=0
We calculate terms in parentheses: -(4x-8(-1x+2)), so:
4x-8(-1x+2)
We multiply parentheses
4x+8x-16
We add all the numbers together, and all the variables
12x-16
Back to the equation:
-(12x-16)
We add all the numbers together, and all the variables
-4x-(12x-16)+16=0
We get rid of parentheses
-4x-12x+16+16=0
We add all the numbers together, and all the variables
-16x+32=0
We move all terms containing x to the left, all other terms to the right
-16x=-32
x=-32/-16
x=+2

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