3(4-2x)+4+2x=4x-8(2-x)

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Solution for 3(4-2x)+4+2x=4x-8(2-x) equation: 



3(4-2x)+4+2x=4x-8(2-x)

We move all terms to the left:

3(4-2x)+4+2x-(4x-8(2-x))=0

We add all the numbers together, and all the variables

3(-2x+4)+2x-(4x-8(-1x+2))+4=0

We add all the numbers together, and all the variables

2x+3(-2x+4)-(4x-8(-1x+2))+4=0

We multiply parentheses

2x-6x-(4x-8(-1x+2))+12+4=0



We calculate terms in parentheses: -(4x-8(-1x+2)), so:

4x-8(-1x+2)

We multiply parentheses

4x+8x-16

We add all the numbers together, and all the variables

12x-16

Back to the equation:

-(12x-16)



We add all the numbers together, and all the variables

-4x-(12x-16)+16=0

We get rid of parentheses

-4x-12x+16+16=0

We add all the numbers together, and all the variables

-16x+32=0

We move all terms containing x to the left, all other terms to the right

-16x=-32

x=-32/-16

x=+2

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