3(4-3x)=x+5(x-2)

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Solution for 3(4-3x)=x+5(x-2) equation: 



3(4-3x)=x+5(x-2)

We move all terms to the left:

3(4-3x)-(x+5(x-2))=0

We add all the numbers together, and all the variables

3(-3x+4)-(x+5(x-2))=0

We multiply parentheses

-9x-(x+5(x-2))+12=0



We calculate terms in parentheses: -(x+5(x-2)), so:

x+5(x-2)

We multiply parentheses

x+5x-10

We add all the numbers together, and all the variables

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

-9x-6x+10+12=0

We add all the numbers together, and all the variables

-15x+22=0

We move all terms containing x to the left, all other terms to the right

-15x=-22

x=-22/-15

x=1+7/15

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