3(4-6x)+18x=12

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Solution for 3(4-6x)+18x=12 equation: 



3(4-6x)+18x=12

We move all terms to the left:

3(4-6x)+18x-(12)=0

We add all the numbers together, and all the variables

3(-6x+4)+18x-12=0

We add all the numbers together, and all the variables

18x+3(-6x+4)-12=0

We multiply parentheses

18x-18x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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