3(4-a)-27=17a-5(3+4a)

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Solution for 3(4-a)-27=17a-5(3+4a) equation:


Simplifying
3(4 + -1a) + -27 = 17a + -5(3 + 4a)
(4 * 3 + -1a * 3) + -27 = 17a + -5(3 + 4a)
(12 + -3a) + -27 = 17a + -5(3 + 4a)

Reorder the terms:
12 + -27 + -3a = 17a + -5(3 + 4a)

Combine like terms: 12 + -27 = -15
-15 + -3a = 17a + -5(3 + 4a)
-15 + -3a = 17a + (3 * -5 + 4a * -5)
-15 + -3a = 17a + (-15 + -20a)

Reorder the terms:
-15 + -3a = -15 + 17a + -20a

Combine like terms: 17a + -20a = -3a
-15 + -3a = -15 + -3a

Add '15' to each side of the equation.
-15 + 15 + -3a = -15 + 15 + -3a

Combine like terms: -15 + 15 = 0
0 + -3a = -15 + 15 + -3a
-3a = -15 + 15 + -3a

Combine like terms: -15 + 15 = 0
-3a = 0 + -3a
-3a = -3a

Add '3a' to each side of the equation.
-3a + 3a = -3a + 3a

Combine like terms: -3a + 3a = 0
0 = -3a + 3a

Combine like terms: -3a + 3a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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