3(4-b)-27=17b-5(3+4b)

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Solution for 3(4-b)-27=17b-5(3+4b) equation:


Simplifying
3(4 + -1b) + -27 = 17b + -5(3 + 4b)
(4 * 3 + -1b * 3) + -27 = 17b + -5(3 + 4b)
(12 + -3b) + -27 = 17b + -5(3 + 4b)

Reorder the terms:
12 + -27 + -3b = 17b + -5(3 + 4b)

Combine like terms: 12 + -27 = -15
-15 + -3b = 17b + -5(3 + 4b)
-15 + -3b = 17b + (3 * -5 + 4b * -5)
-15 + -3b = 17b + (-15 + -20b)

Reorder the terms:
-15 + -3b = -15 + 17b + -20b

Combine like terms: 17b + -20b = -3b
-15 + -3b = -15 + -3b

Add '15' to each side of the equation.
-15 + 15 + -3b = -15 + 15 + -3b

Combine like terms: -15 + 15 = 0
0 + -3b = -15 + 15 + -3b
-3b = -15 + 15 + -3b

Combine like terms: -15 + 15 = 0
-3b = 0 + -3b
-3b = -3b

Add '3b' to each side of the equation.
-3b + 3b = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = -3b + 3b

Combine like terms: -3b + 3b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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