3(4-c)-22=17c-5(2+4c)

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Solution for 3(4-c)-22=17c-5(2+4c) equation:


Simplifying
3(4 + -1c) + -22 = 17c + -5(2 + 4c)
(4 * 3 + -1c * 3) + -22 = 17c + -5(2 + 4c)
(12 + -3c) + -22 = 17c + -5(2 + 4c)

Reorder the terms:
12 + -22 + -3c = 17c + -5(2 + 4c)

Combine like terms: 12 + -22 = -10
-10 + -3c = 17c + -5(2 + 4c)
-10 + -3c = 17c + (2 * -5 + 4c * -5)
-10 + -3c = 17c + (-10 + -20c)

Reorder the terms:
-10 + -3c = -10 + 17c + -20c

Combine like terms: 17c + -20c = -3c
-10 + -3c = -10 + -3c

Add '10' to each side of the equation.
-10 + 10 + -3c = -10 + 10 + -3c

Combine like terms: -10 + 10 = 0
0 + -3c = -10 + 10 + -3c
-3c = -10 + 10 + -3c

Combine like terms: -10 + 10 = 0
-3c = 0 + -3c
-3c = -3c

Add '3c' to each side of the equation.
-3c + 3c = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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