3(4-q)=32+q

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Solution for 3(4-q)=32+q equation: 



3(4-q)=32+q

We move all terms to the left:

3(4-q)-(32+q)=0

We add all the numbers together, and all the variables

3(-1q+4)-(q+32)=0

We multiply parentheses

-3q-(q+32)+12=0

We get rid of parentheses

-3q-q-32+12=0

We add all the numbers together, and all the variables

-4q-20=0

We move all terms containing q to the left, all other terms to the right

-4q=20

q=20/-4

q=-5

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