3(4-x)+5(x-3)=8-2(x+1)-2/7x

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Solution for 3(4-x)+5(x-3)=8-2(x+1)-2/7x equation: 



3(4-x)+5(x-3)=8-2(x+1)-2/7x

We move all terms to the left:

3(4-x)+5(x-3)-(8-2(x+1)-2/7x)=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3(-1x+4)+5(x-3)-(8-2(x+1)-2/7x)=0

We multiply parentheses

-3x+5x-(8-2(x+1)-2/7x)+12-15=0

We multiply all the terms by the denominator


-3x*7x)+5x*7x)-(8-2(x+1)-2+12*7x)-15*7x)=0

Wy multiply elements

-147x^3+1)-2+12*7x)-15*7x)=0

We do not support expression: x^3

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