3(4-x)+6x=4x+12-x

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Solution for 3(4-x)+6x=4x+12-x equation: 



3(4-x)+6x=4x+12-x

We move all terms to the left:

3(4-x)+6x-(4x+12-x)=0

We add all the numbers together, and all the variables

3(-1x+4)+6x-(3x+12)=0

We add all the numbers together, and all the variables

6x+3(-1x+4)-(3x+12)=0

We multiply parentheses

6x-3x-(3x+12)+12=0

We get rid of parentheses

6x-3x-3x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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